As of April 01, 2026, the average annual salary for Quantitative Developer in Seaford, DE is $112,399, equivalent to $54 per hour, $2,162 weekly, or $9,367 monthly. These figures, sourced from Salary.com’s real-time job posting scans, highlight competitive earning potential for Quantitative Developer in cities like Santa Clara, San Jose, and Fremont.

Annually Salaries for Quantitative Developer in Seaford, DE vary widely, spanning from $94,221 to $129,821. Most professionals fall between the 25th percentile ($102,884) and 75th percentile ($121,518), while top earners (90th percentile) make $129,821 per year. This $18,634 pay gap underscores opportunities for salary growth through certifications, specialized skills like Analysis or Installation, or targeting high-paying regions like District of Columbia or California.

Location and experience significantly influence earnings. For example, Seaford Quantitative Developer often earn 2.4% higher than national averages. However, Seaford currently ranks 249 statewide for Quantitative Developer job salary. Professionals are advised to focus on high-growth sectors like to offset market challenges.

Based on HR-reported data: a national average with a geographic differential
Quantitative Developer Salaries by Percentile
Percentile Salary Location Last Updated
10th Percentile Quantitative Developer Salary $94,221 Seaford, DE April 01, 2026
25th Percentile Quantitative Developer Salary $102,884 Seaford, DE April 01, 2026
50th Percentile Quantitative Developer Salary $112,399 Seaford, DE April 01, 2026
75th Percentile Quantitative Developer Salary $121,518 Seaford, DE April 01, 2026
90th Percentile Quantitative Developer Salary $129,821 Seaford, DE April 01, 2026
25% $102,884 10% $94,221 90% $129,821 75% $121,518 $112,399 50%(Median) Didn’t find job title? Click
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Quantitative Developer

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Average Base Salary

Core compensation

 
 
 
102884
121518
112399

Average Total Cash Compensation

Includes base and annual incentives

 
 
 
112619
140317
125857
These charts show the average base salary (core compensation), as well as the average total cash compensation for the job of Quantitative Developer in Seaford, DE. The base salary for Quantitative Developer ranges from $102,884 to $121,518 with the average base salary of $112,399. The total cash compensation, which includes base, and annual incentives, can vary anywhere from $112,619 to $140,317 with the average total cash compensation of $125,857.

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102884
121518

 

About Seaford, Delaware    Seaford is a city located along the Nanticoke River in Sussex County, Delaware. According to the 2010 Census Bureau figures, the population of the ci....More

Seaford, Delaware  area prices were up 1.0% from a year ago

Quantitative Developer Salary in popular cities: WilmingtonDoverNewark

Skills associated with Quantitative Developer: Trading

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