As of July 01, 2026, the average annual salary for Quantitative Developer in Youngstown, OH is $97,956, equivalent to $47 per hour, $1,884 weekly, or $8,163 monthly. These figures, sourced from Salary.com’s real-time job posting scans, highlight competitive earning potential for Quantitative Developer in cities like San Jose, Santa Clara, and San Francisco.

Annually Salaries for Quantitative Developer in Youngstown, OH vary widely, spanning from $82,119 to $113,139. Most professionals fall between the 25th percentile ($89,666) and 75th percentile ($105,904), while top earners (90th percentile) make $113,139 per year. This $16,238 pay gap underscores opportunities for salary growth through certifications, specialized skills like Analysis or Installation, or targeting high-paying regions like District of Columbia or California.

Location and experience significantly influence earnings. For example, Youngstown Quantitative Developer often earn 7.2% lower than national averages. However, Youngstown currently ranks 726 statewide for Quantitative Developer job salary. Professionals are advised to focus on high-growth sectors like to offset market challenges.

Based on HR-reported data: a national average with a geographic differential
Quantitative Developer Salaries by Percentile
Percentile Salary Location Last Updated
10th Percentile Quantitative Developer Salary $82,119 Youngstown, OH July 01, 2026
25th Percentile Quantitative Developer Salary $89,666 Youngstown, OH July 01, 2026
50th Percentile Quantitative Developer Salary $97,956 Youngstown, OH July 01, 2026
75th Percentile Quantitative Developer Salary $105,904 Youngstown, OH July 01, 2026
90th Percentile Quantitative Developer Salary $113,139 Youngstown, OH July 01, 2026
25% $89,666 10% $82,119 90% $113,139 75% $105,904 $97,956 50%(Median) Didn’t find job title? Click
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Quantitative Developer

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Job Openings for Quantitative Developer in Youngstown, OH

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Average Base Salary

Core compensation

 
 
 
89666
105904
97956

Average Total Cash Compensation

Includes base and annual incentives

 
 
 
98884
123203
110506
These charts show the average base salary (core compensation), as well as the average total cash compensation for the job of Quantitative Developer in Youngstown, OH. The base salary for Quantitative Developer ranges from $89,666 to $105,904 with the average base salary of $97,956. The total cash compensation, which includes base, and annual incentives, can vary anywhere from $98,884 to $123,203 with the average total cash compensation of $110,506.

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89666
105904

 

About Youngstown, Ohio    Youngstown is a city in and the county seat of Mahoning County in the U.S. state of Ohio, with small portions extending into Trumbull County. Accordin....More

Youngstown, Ohio  area prices were up 1.3% from a year ago

Quantitative Developer Salary in popular cities: ColumbusClevelandCincinnati

Skills associated with Quantitative Developer: Trading

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