As of November 01, 2026, the average annual salary for Ruby Programmer in Seaford, DE is $92,848, equivalent to $45 per hour, $1,786 weekly, or $7,737 monthly. These figures, sourced from Salary.com’s real-time job posting scans, highlight competitive earning potential for Ruby Programmer in cities like San Jose, Santa Clara, and San Francisco.

Annually Salaries for Ruby Programmer in Seaford, DE vary widely, spanning from $75,689 to $107,106. Most professionals fall between the 25th percentile ($83,866) and 75th percentile ($100,311), while top earners (90th percentile) make $107,106 per year. This $16,445 pay gap underscores opportunities for salary growth through certifications, specialized skills like Analysis or Application Development, or targeting high-paying regions like District of Columbia or California.

Location and experience significantly influence earnings. For example, Seaford Ruby Programmer often earn 0.5% higher than national averages. However, Seaford currently ranks 315 statewide for Ruby Programmer job salary. Professionals are advised to focus on high-growth sectors like to offset market challenges.

Based on HR-reported data: a national average with a geographic differential
Ruby Programmer Salaries by Percentile
Percentile Salary Location Last Updated
10th Percentile Ruby Programmer Salary $75,689 Seaford, DE November 01, 2026
25th Percentile Ruby Programmer Salary $83,866 Seaford, DE November 01, 2026
50th Percentile Ruby Programmer Salary $92,848 Seaford, DE November 01, 2026
75th Percentile Ruby Programmer Salary $100,311 Seaford, DE November 01, 2026
90th Percentile Ruby Programmer Salary $107,106 Seaford, DE November 01, 2026
25% $83,866 10% $75,689 90% $107,106 75% $100,311 $92,848 50%(Median) Didn’t find job title? Click
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Average Base Salary

Core compensation

 
 
 
83866
100311
92848

Average Total Cash Compensation

Includes base and annual incentives

 
 
 
91275
118686
104086
These charts show the average base salary (core compensation), as well as the average total cash compensation for the job of Ruby Programmer in Seaford, DE. The base salary for Ruby Programmer ranges from $83,866 to $100,311 with the average base salary of $92,848. The total cash compensation, which includes base, and annual incentives, can vary anywhere from $91,275 to $118,686 with the average total cash compensation of $104,086.

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83866
100311

 

About Seaford, Delaware    Seaford is a city located along the Nanticoke River in Sussex County, Delaware. According to the 2010 Census Bureau figures, the population of the ci....More

Seaford, Delaware  area prices were up 1.0% from a year ago

Ruby Programmer Salary in popular cities: Wilmington, Dover, Newark

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