As of March 01, 2026, the average annual salary for Ruby Programmer in Seaford, DE is $95,623, equivalent to $46 per hour, $1,839 weekly, or $7,969 monthly. These figures, sourced from Salary.com’s real-time job posting scans, highlight competitive earning potential for Ruby Programmer in cities like Santa Clara, San Jose, and Fremont.

Annually Salaries for Ruby Programmer in Seaford, DE vary widely, spanning from $77,886 to $110,232. Most professionals fall between the 25th percentile ($86,339) and 75th percentile ($103,270), while top earners (90th percentile) make $110,232 per year. This $16,931 pay gap underscores opportunities for salary growth through certifications, specialized skills like Analysis or Application Development, or targeting high-paying regions like District of Columbia or California.

Location and experience significantly influence earnings. For example, Seaford Ruby Programmer often earn 2.4% higher than national averages. However, Seaford currently ranks 249 statewide for Ruby Programmer job salary. Professionals are advised to focus on high-growth sectors like to offset market challenges.

Based on HR-reported data: a national average with a geographic differential
Ruby Programmer Salaries by Percentile
Percentile Salary Location Last Updated
10th Percentile Ruby Programmer Salary $77,886 Seaford, DE March 01, 2026
25th Percentile Ruby Programmer Salary $86,339 Seaford, DE March 01, 2026
50th Percentile Ruby Programmer Salary $95,623 Seaford, DE March 01, 2026
75th Percentile Ruby Programmer Salary $103,270 Seaford, DE March 01, 2026
90th Percentile Ruby Programmer Salary $110,232 Seaford, DE March 01, 2026
25% $86,339 10% $77,886 90% $110,232 75% $103,270 $95,623 50%(Median) Didn’t find job title? Click
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Ruby Programmer

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Job Openings for Ruby Programmer in Seaford, DE

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Average Base Salary

Core compensation

 
 
 
86339
103270
95623

Average Total Cash Compensation

Includes base and annual incentives

 
 
 
92102
119763
105030
These charts show the average base salary (core compensation), as well as the average total cash compensation for the job of Ruby Programmer in Seaford, DE. The base salary for Ruby Programmer ranges from $86,339 to $103,270 with the average base salary of $95,623. The total cash compensation, which includes base, and annual incentives, can vary anywhere from $92,102 to $119,763 with the average total cash compensation of $105,030.

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86339
103270

 

About Seaford, Delaware    Seaford is a city located along the Nanticoke River in Sussex County, Delaware. According to the 2010 Census Bureau figures, the population of the ci....More

Seaford, Delaware  area prices were up 1.0% from a year ago

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