Active ingredient technician Salary in Sioux City, IA Comparison by Location
Nationwide
United States
$48,792
Sioux City
Iowa
$43,376
How much does an Active ingredient technician make in Sioux City, IA?
As of March 01, 2025, an Active ingredient technician in Sioux City,
IA earns an average salary of $43,376 per year.
An Active ingredient technician's salary in Sioux City, IA
can be paid hourly, weekly, or monthly depending on the company and job type.
Most part-time jobs will be paid hourly or weekly.
Using the salary calculator,
the average pay comes out to be about $21 an hour
or $834/week,
or $3,615/month.
The average salary for an Active ingredient technician ranges
from $36,281 to $52,703.
The average salary range for Active ingredient technician varies widely,
which indicates that there are many opportunities for advancement, promotions, and salary increases.
These opportunities depend on many factors, including skills, education, certifications, location, and years of experience.
Sioux city is ranked 834th out of 938 cities
in the state of Iowa for Active ingredient technician salaries.
Salary.com helps you determine your exact pay target
by estimating the most accurate annual salary range for Active ingredient technician jobs,
with more online, real-time compensation data than any other website.
Check outActive ingredient technicianjobs inSioux City, Iowa