As of April 01, 2026, the average annual salary for Cobol Developer in Brownsville, TX is $78,297, equivalent to $38 per hour, $1,506 weekly, or $6,525 monthly. These figures, sourced from Salary.com’s real-time job posting scans, highlight competitive earning potential for Cobol Developer in cities like Santa Clara, San Jose, and Fremont.

Annually Salaries for Cobol Developer in Brownsville, TX vary widely, spanning from $62,667 to $93,087. Most professionals fall between the 25th percentile ($70,116) and 75th percentile ($86,039), while top earners (90th percentile) make $93,087 per year. This $15,923 pay gap underscores opportunities for salary growth through certifications, specialized skills like Analysis or Software Development, or targeting high-paying regions like District of Columbia or California.

Location and experience significantly influence earnings. For example, Brownsville Cobol Developer often earn 11.6% lower than national averages. However, Brownsville currently ranks 796 statewide for Cobol Developer job salary. Professionals are advised to focus on high-growth sectors like to offset market challenges.

Based on HR-reported data: a national average with a geographic differential
Cobol Developer Salaries by Percentile
Percentile Salary Location Last Updated
10th Percentile Cobol Developer Salary $62,667 Brownsville, TX April 01, 2026
25th Percentile Cobol Developer Salary $70,116 Brownsville, TX April 01, 2026
50th Percentile Cobol Developer Salary $78,297 Brownsville, TX April 01, 2026
75th Percentile Cobol Developer Salary $86,039 Brownsville, TX April 01, 2026
90th Percentile Cobol Developer Salary $93,087 Brownsville, TX April 01, 2026
25% $70,116 10% $62,667 90% $93,087 75% $86,039 $78,297 50%(Median) Didn’t find job title? Click
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Cobol Developer

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Average Base Salary

Core compensation

 
 
 
70116
86039
78297

Average Total Cash Compensation

Includes base and annual incentives

 
 
 
72809
96742
84026
These charts show the average base salary (core compensation), as well as the average total cash compensation for the job of Cobol Developer in Brownsville, TX. The base salary for Cobol Developer ranges from $70,116 to $86,039 with the average base salary of $78,297. The total cash compensation, which includes base, and annual incentives, can vary anywhere from $72,809 to $96,742 with the average total cash compensation of $84,026.

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70116
86039

 

About Brownsville, Texas    Brownsville is one of the southernmost cities in the contiguous United States; only a handful of municipalities in Florida's Miami-Dade and Monroe cou....More

Brownsville, Texas  area prices were up 1.2% from a year ago

Cobol Developer Salary in popular cities: HoustonSan AntonioDallas

Skills associated with Cobol Developer: User

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